Python – Print Heart Pattern
Last Updated :
05 Aug, 2022
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Given an even integer input, the task is to write a Python program to print a heart using loops and mathematical formulations.
Example :
For n = 8
* * * *
* * *
* *
* G F G *
* *
* *
* *
*
For n = 14
* * * *
* * * *
* * * *
* * *
* *
* G F G *
* *
* *
* *
* *
* *
* *
*
Approach :
The following steps are used :
- Form the worksheet of n X n+1 using two loops.
- Apply the if-else conditions for printing stars.
- Apply the if-else conditions for printing text “GFG”.
- Apply else condition for rest spaces.
Note: The value of n must be greater than 8
Below is the implementation of the above approach :
Python3
# define size n = even onlyn = 8# so this heart can be made n//2 part left,# n//2 part right, and one middle line# i.e; columns m = n + 1m = n+1# loops for upper partfor i in range(n//2-1): for j in range(m): # condition for printing stars to GFG upper line if i == n//2-2 and (j == 0 or j == m-1): print("*", end=" ") # condition for printing stars to left upper elif j <= m//2 and ((i+j == n//2-3 and j <= m//4) \ or (j-i == m//2-n//2+3 and j > m//4)): print("*", end=" ") # condition for printing stars to right upper elif j > m//2 and ((i+j == n//2-3+m//2 and j < 3*m//4) \ or (j-i == m//2-n//2+3+m//2 and j >= 3*m//4)): print("*", end=" ") # condition for printing spaces else: print(" ", end=" ") print()# loops for lower partfor i in range(n//2-1, n): for j in range(m): # condition for printing stars if (i-j == n//2-1) or (i+j == n-1+m//2): print('*', end=" ") # condition for printing GFG elif i == n//2-1: if j == m//2-1 or j == m//2+1: print('G', end=" ") elif j == m//2: print('F', end=" ") else: print(' ', end=" ") # condition for printing spaces else: print(' ', end=" ") print() |
Output:
* * * *
* * * *
* * * *
* * *
* *
* G F G *
* *
* *
* *
* *
* *
* *
*
Time complexity: O(n2) for given input n
Auxiliary Space: O(1)
