numpy.isinf() in Python
Last Updated :
08 Mar, 2024
Improve
The numpy.isinf() function tests element-wise whether it is +ve or -ve infinity or not return the result as a boolean array.
Syntax: numpy.isinf(array [, out])
Parameters :
array : [array_like]Input array or object whose
elements, we need to test for infinity
out : [ndarray, optional]Output array placed
with result. Its type is preserved and
it must be of the right shape to hold
the output.
Return :
boolean array containing the result. For scalar input, the result is a new boolean with value True if the input is positive or negative infinity; otherwise the value is False. For array input, the result is a boolean array with the same shape as the input and the values are True where the corresponding element of the input is positive or negative infinity; elsewhere the values are False.
Code 1 :
Python
# Python Program illustrating # numpy.isinf() method import numpy as geek print("Finite : ", geek.isinf(1), "\n") print("Finite : ", geek.isinf(0), "\n") # not a number print("Finite : ", geek.isinf(geek.nan), "\n") # infinity print("Finite : ", geek.isinf(geek.inf), "\n") print("Finite : ", geek.isinf(geek.NINF), "\n") x = geek.array([-geek.inf, 0., geek.inf]) y = geek.array([2, 2, 2]) print("Checking for infinity : ", geek.isinf(x, y)) |
Output :
Finite : False Finite : False Finite : False Finite : True Finite : True Checking for infinity : [1 0 1]
Code 2 :
Python
# Python Program illustrating # numpy.isinf() method import numpy as geek # Returns True/False value for each element b = geek.arange(8).reshape(2, 4) print("\n",b) print("\nIs Infinity : \n", geek.isinf(b)) # geek.inf : Positive Infinity # geek.NINF : negative Infinity b = [[geek.inf], [geek.NINF]] print("\nIs Infinity : \n", geek.isinf(b)) |
Output :
[[0 1 2 3] [4 5 6 7]] Is Infinity : [[False False False False] [False False False False]] Is Infinity : [[ True] [ True]]
Note :
These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.
Improve
