Any and All are two built ins provided in python used for successive And/Or.
Any
Returns true if any of the items is True. It returns False if empty or all are false. Any can be thought of as a sequence of OR operations on the provided iterables.
It short circuit the execution i.e. stop the execution as soon as the result is known.
Syntax : any(list of iterables)
# Since all are false, false is returned print (any([False, False, False, False])) # Here the method will short-circuit at the # second item (True) and will return True. print (any([False, True, False, False])) # Here the method will short-circuit at the # first (True) and will return True. print (any([True, False, False, False])) |
Output :
False True True
All
Returns true if all of the items are True (or if the iterable is empty). All can be thought of as a sequence of AND operations on the provided iterables. It also short circuit the execution i.e. stop the execution as soon as the result is known.
Syntax : all(list of iterables)
# Here all the iterables are True so all # will return True and the same will be printed print (all([True, True, True, True])) # Here the method will short-circuit at the # first item (False) and will return False. print (all([False, True, True, False])) # This statement will return False, as no # True is found in the iterables print (all([False, False, False])) |
Output :
True False False
Practical Examples
# This code explains how can we # use 'any' function on list list1 = [] list2 = [] # Index ranges from 1 to 10 to multiply for i in range(1,11): list1.append(4*i) # Index to access the list2 is from 0 to 9 for i in range(0,10): list2.append(list1[i]%5==0) print('See whether at least one number is divisible by 5 in list 1=>') print(any(list2)) |
Output:
See whether at least one number is divisible by 5 in list 1=> True
# Illustration of 'all' function in python 3 # Take two lists list1=[] list2=[] # All numbers in list1 are in form: 4*i-3 for i in range(1,21): list1.append(4*i-3) # list2 stores info of odd numbers in list1 for i in range(0,20): list2.append(list1[i]%2==1) print('See whether all numbers in list1 are odd =>') print(all(list2)) |
Output:
See whether all numbers in list1 are odd => True
Truth table :-
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Improved By : pritam_pranjay
