set copy() in python
The copy() method returns a shallow copy of the set in python. If we use “=” to copy a set to another set, when we modify in the copied set, the changes are also reflected in the original set. So we have to create a shallow copy of the set such that when we modify something in the copied set, changes are not reflected back in the original set.
Syntax:
set_name.copy()
set_name: Name of the set whose copy
we want to generate.
Parameters:The copy() method for sets doesn’t take any parameters.
Return value:The function returns a shallow copy of the original set.
Below is the implementation of the above function:
# Python3 program to demonstrate the use # of join() function set1 = {1, 2, 3, 4} # function to copy the set set2 = set1.copy() # prints the copied set print(set2) |
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Output:
{1, 2, 3, 4}
Shallow Copy Example :
# Python program to demonstrate that copy # created using set copy is shallow first = {'g', 'e', 'e', 'k', 's'} second = first.copy() # before adding print 'before adding: 'print 'first: ',first print 'second: ', second # Adding element to second, first does not # change. second.add('f') # after adding print 'after adding: 'print 'first: ', first print 'second: ', second |
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Output:
before adding: first: set(['s', 'e', 'k', 'g']) second: set(['s', 'e', 'k', 'g']) after adding: first: set(['s', 'e', 'k', 'g']) second: set(['s', 'e', 'k', 'g', 'f'])
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